20年三道编程大题

题库有些简单，换新的题来写一下，自从20年之后，专业课难度感觉直线飙升啊。

第一题-字符串中找出英文数组

#include<stdio.h>
#include<string.h>

void fun(char str[], char *p) {
	int len;
	len = strlen(str);
	char item;
	int cishu = 0;
	for (int i = 0; i < len; i++) {
		if ((('a' <= str[i]) && ('z' >= str[i])) || (('A' <= str[i]) && ('Z' >= str[i]))) {
			item = str[i];
			for (int j = i; j < len-1; j++) {
				str[j] = str[j + 1];
			}
			str[len - 1] = item;
			i--;//避免有连续的字母，这样就可以不断检测这一位是否是字母
		}
		cishu++;
		if (cishu >= len) {//避免无限循环
			return;
		}
	}
}

int main() {
	printf("请输入一串字符串：");
	char ch[128] = "";
	char* p;
	p = ch;
	scanf("%s", ch);
	fun(ch, p);
	printf("\n处理如下：%s", ch);
	return 0;
}

第二题-求数组列和

#include <stdio.h>
#include <string.h>
int fun(int arr[][3], int n);

int main()
{
	//我们这里就求一个3行3列数组的第一列和最后一列之和。
	int arr[3][3] = { {1,2,3},{7,8,2},{2,3,4} };
	printf("%d", fun(arr, 3));
}

int fun(int arr[][3], int n) {//n为n行数组的意思
	int sum = 0;
	for (int i = 0; i < n; i++) {
		//循环第一列
		sum += arr[i][0];
	}

	for (int i = 0; i < n; i++) {
		//循环最后一列
		sum += arr[i][2];
	}
	return sum;
}

第三题-结构体指针

#include <stdio.h>
#include <string.h>

struct Student {
	char name[20];
	int english;
	int math;
	int politics;
	int specialised;
	int SUM = english + math + politics + specialised;
};

int fun(struct Student aa[], int (*p)(struct Student aa[])) {
	//p指向fun2
	return 	p(aa);;
}

int fun2(struct Student aa[]);

int main()
{

	struct Student aa[4] = {
	{"越江", 65, 85, 60, 110},
	{"张三", 77, 100, 60, 60},
	{"李四", 60, 60, 60, 60},
	{"王五", 75, 75, 75, 75}
	};
	int max_index = fun(aa,fun2);
	printf("获得最高分的是国服%s，分数为：%d", aa[max_index].name, aa[max_index].SUM);
}


int fun2(struct Student aa[]) {
	int av_english, av_math, av_politcs, av_specialised;
	char av_name[20];
	int sum = 0;
	int sum2 = 0;
	int sum3 = 0;
	int sum4 = 0;
	for (int i = 0; i < 4; i++) {
		sum += aa[i].english;
		sum2 += aa[i].math;
		sum3 += aa[i].politics;
		sum4 += aa[i].specialised;
	}
	av_english = sum / 4;
	av_math = sum2 / 4;
	av_politcs = sum3 / 4;
	av_specialised = sum4 / 4;
	printf("平均成绩\n英语：%d\n数学：%d\n政治：%d\n专业课：%d\n", av_english, av_math, av_politcs, av_specialised);

	int max_index = 0;//只记录一个最大分就可
	for (int i = 0; i < 4; i++) {
		if (aa[i].SUM > aa[max_index].SUM) {
			max_index = i;
		}
	}

	return max_index;
}